Question

12 type the full electron configuration for silicon. do not leave spaces between your terms and do not attempt superscripts (for example: 1s22s1).

Explanation:

Step1: Determine atomic number of Si

Silicon (Si) has an atomic number of 14, meaning it has 14 electrons.

Step2: Apply Aufbau principle

Fill orbitals in order: 1s, 2s, 2p, 3s, 3p.

• 1s holds 2: \(1s^2\) (but written as 1s2 here)
• 2s holds 2: \(2s^2\) → 2s2
• 2p holds 6: \(2p^6\) → 2p6
• 3s holds 2: \(3s^2\) → 3s2
• Remaining electrons: \(14 - (2 + 2 + 6 + 2) = 2\)? Wait, no: Wait, 2+2+6+2=12, remaining 2? No, wait, 14 total. Wait, 1s2 (2), 2s2 (2, total 4), 2p6 (6, total 10), 3s2 (2, total 12), then 3p2 (since 14 - 12 = 2). So 3p2.

Combine: 1s22s22p63s23p2.

Answer:

1s22s22p63s23p2