Question

1. if 125 ml of a 0.15m naoh solution is diluted to a final volume of 150 ml, what will be the molarity of the diluted solution?

1. if 100. ml of a 0.15 m naoh solution is diluted to a final volume of 175 ml, what will be the molarity of the diluted solution?

1. how many liters of a 0.050 m hcl solution can be made by diluting 250 ml of 10. m hcl solution?

1. 345 ml of a 1.5 m nacl solution is boiled until the volume of the solution is 250. ml, what is the new molarity of the solution?

1. how many liters will be made when 500 ml of a 2.4 m kcl solution is diluted to a 1.0 m solution?

ans 1) 0.13 m 2) 0.086 m 3) 50. l 4) 2.1 m 5) 1 l

Explanation:

Question 1

Step1: Recall dilution formula

The dilution formula is \( M_1V_1 = M_2V_2 \), where \( M_1 \) is initial molarity, \( V_1 \) is initial volume, \( M_2 \) is final molarity, \( V_2 \) is final volume.
Here, \( M_1 = 0.15 \, M \), \( V_1 = 125 \, mL \), \( V_2 = 150 \, mL \), find \( M_2 \).

Step2: Rearrange formula for \( M_2 \)

\( M_2=\frac{M_1V_1}{V_2} \)

Step3: Substitute values

\( M_2=\frac{0.15 \, M\times125 \, mL}{150 \, mL} \)
\( M_2=\frac{18.75}{150} \, M = 0.125 \, M\approx0.13 \, M \)

Step1: Use dilution formula \( M_1V_1 = M_2V_2 \)

\( M_1 = 0.15 \, M \), \( V_1 = 100 \, mL \), \( V_2 = 175 \, mL \), find \( M_2 \).

Step2: Rearrange for \( M_2 \)

\( M_2=\frac{M_1V_1}{V_2} \)

Step3: Substitute values

\( M_2=\frac{0.15 \, M\times100 \, mL}{175 \, mL} \)
\( M_2=\frac{15}{175} \, M\approx0.0857 \, M\approx0.086 \, M \)

Step1: Apply dilution formula \( M_1V_1 = M_2V_2 \)

\( M_1 = 10. \, M \), \( V_1 = 250 \, mL = 0.25 \, L \), \( M_2 = 0.050 \, M \), find \( V_2 \).

Step2: Rearrange for \( V_2 \)

\( V_2=\frac{M_1V_1}{M_2} \)

Step3: Substitute values

\( V_2=\frac{10. \, M\times0.25 \, L}{0.050 \, M} \)
\( V_2=\frac{2.5}{0.050} \, L = 50. \, L \)

Answer:

\( 0.13 \, M \)

Question 2