QUESTION IMAGE
Question
- $8c^2 - c + 3 + 2c^2 - c + 2$
- $6a^2b^2 + 3ab^2 - a^2b^2 - 4ab^2$
- write the perimeter of the rectangle as a simplified expression.
rectangle with length $7x + 1$ and width $x - 3$
Response
Problem 15: Simplify \( 8c^2 - c + 3 + 2c^2 - c + 2 \)
Step1: Combine like terms for \( c^2 \)
\( 8c^2 + 2c^2 = (8 + 2)c^2 = 10c^2 \)
Step2: Combine like terms for \( c \)
\( -c - c = (-1 - 1)c = -2c \)
Step3: Combine constant terms
\( 3 + 2 = 5 \)
Step4: Combine all simplified terms
\( 10c^2 - 2c + 5 \)
Step1: Combine like terms for \( a^2b^2 \)
\( 6a^2b^2 - a^2b^2 = (6 - 1)a^2b^2 = 5a^2b^2 \)
Step2: Combine like terms for \( ab^2 \)
\( 3ab^2 - 4ab^2 = (3 - 4)ab^2 = -ab^2 \)
Step3: Combine all simplified terms
\( 5a^2b^2 - ab^2 \)
Step1: Substitute length and width into the perimeter formula
\( P = 2[(7x + 1) + (x - 3)] \)
Step2: Simplify inside the parentheses
\( (7x + 1) + (x - 3) = 7x + x + 1 - 3 = 8x - 2 \)
Step3: Multiply by 2
\( P = 2(8x - 2) = 16x - 4 \)
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\( 10c^2 - 2c + 5 \)