Question

1. you determined the water potential of the potato to be -9.8 bars. you determined the water potential of the celery to be -9.92 bars. compare their water potential, osmolarity, and solute concentrations. potato water potential a osmolarity c solute concentration e celery water potential b osmolarity d solute concentration f

Explanation:

1. Water Potential: Water potential is measured directly here; the given value for Potato is -9.8 bars, and for Celery is -9.92 bars.
2. Osmolarity: The osmolarity of a solution is equal to the solute concentration for ionic compounds like NaCl (since NaCl dissociates into 2 ions, but the molarity on the graph corresponds to osmolarity for this context). The linear fit crosses 0% mass change (isotonic point, where water potential matches the tissue) at ~0.18 M NaCl, so osmolarity is ~0.18 osmol/L. Since Potato and Celery have very close water potentials, their osmolarities are nearly equal, with Celery's slightly higher to match its lower water potential.
3. Solute Concentration: For NaCl, solute concentration (molarity) is half the osmolarity (due to dissociation into Na⁺ and Cl⁻). For Potato, $\frac{0.18}{2}=0.09$ M; for Celery, a slightly higher ~0.095 M to align with -9.92 bars.

Answer:

	Potato	Celery
Osmolarity	C. ~0.18 osmol/L	D. ~0.19 osmol/L
Solute Concentration	E. ~0.09 M NaCl	F. ~0.095 M NaCl