Question

16.) evaluate \\(\frac{2b + c^2}{a}\\), if \\(a = 2, b = 4,\\) and \\(c = 6\\).
17.) evaluate the expression \\(4a + 9b - 2c\\) if \\(a = -1, b = 4,\\) and \\(c = 6\\).

Explanation:

Problem 16:

Step1: Substitute the values

Substitute \(a = 2\), \(b = 4\), and \(c = 6\) into the expression \(\frac{2b + c^2}{a}\).
First, calculate \(c^2\): \(c^2 = 6^2 = 36\)
Then, calculate \(2b\): \(2b = 2\times4 = 8\)
Now, the numerator is \(2b + c^2 = 8 + 36 = 44\)

Step2: Divide by \(a\)

Divide the numerator by \(a\) (where \(a = 2\)): \(\frac{44}{2} = 22\)

Step1: Substitute the values

Substitute \(a = -1\), \(b = 4\), and \(c = 6\) into the expression \(4a + 9b - 2c\).
Calculate \(4a\): \(4\times(-1) = -4\)
Calculate \(9b\): \(9\times4 = 36\)
Calculate \(2c\): \(2\times6 = 12\)

Step2: Combine the terms

Now, combine the terms: \(4a + 9b - 2c = -4 + 36 - 12\)
First, \(-4 + 36 = 32\)
Then, \(32 - 12 = 20\)

Answer:

22

Problem 17: