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Question
- subtract the mixed numbers $16 - 9\frac{8}{9}$. $\bigcirc\\ 7\frac{1}{9}$ $\bigcirc\\ 7\frac{8}{9}$ $\bigcirc\\ 6\frac{1}{9}$ $\bigcirc\\ 5\frac{1}{9}$
Step1: Rewrite 16 as a mixed number
We can write \( 16 \) as \( 15 + 1 \), and then rewrite \( 1 \) as a fraction with denominator \( 9 \). So \( 16 = 15\frac{9}{9} \) (since \( 1=\frac{9}{9} \)).
Step2: Subtract the mixed numbers
Now we subtract \( 9\frac{8}{9} \) from \( 15\frac{9}{9} \). First, subtract the whole numbers and then the fractions:
\( 15 - 9 = 6 \) (subtracting the whole number parts)
\( \frac{9}{9}-\frac{8}{9}=\frac{9 - 8}{9}=\frac{1}{9} \) (subtracting the fractional parts)
Then we combine the results: \( 6+\frac{1}{9}=6\frac{1}{9} \)
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\( 6\frac{1}{9} \) (corresponding to the option \( 6\frac{1}{9} \))