Question

20 essay 1 point
$4nh_3(g) + 5o_2(g) \
ightarrow 4no(g) + 6h_2o(g)$
using the above equation, at stp, when 0.675 l of ammonia burns, what volume of water vapor will be formed?
always show your work!

Explanation:

Step1: Identify mole ratio

From the balanced equation: $\frac{V_{\ce{H2O}}}{V_{\ce{NH3}}} = \frac{6}{4}$

Step2: Calculate water vapor volume

Substitute $V_{\ce{NH3}}=0.675\ \text{L}$:
$V_{\ce{H2O}} = 0.675\ \text{L} \times \frac{6}{4}$

Step3: Compute final value

$V_{\ce{H2O}} = 0.675 \times 1.5 = 1.0125\ \text{L}$

Answer:

$1.01\ \text{L}$ (or $1.0125\ \text{L}$)