Question

at 25 °c and 785 torr, carbon dioxide has a solubility of 0.0351 m in water. what is its solubility at 25 °c and 1750 torr? s = m

Explanation:

Step1: Recall Henry's law

Henry's law states that $S_1/P_1 = S_2/P_2$, where $S$ is solubility and $P$ is pressure.

Step2: Identify given values

$S_1 = 0.0351\ M$, $P_1=785\ Torr$, $P_2 = 1750\ Torr$.

Step3: Rearrange formula to solve for $S_2$

$S_2=\frac{S_1\times P_2}{P_1}$.

Step4: Substitute values

$S_2=\frac{0.0351\times1750}{785}$.
$S_2=\frac{61.425}{785}\approx0.0783\ M$.

Answer:

$0.0783$