Question

2.284 g of tin was oxidized through the titration. what is the mass percent of tin in the original 10.00 g ore sample?? % sn

Explanation:

Step1: Recall the formula for mass percent

The formula for mass percent of a component in a sample is $\text{Mass Percent} = \frac{\text{Mass of Component}}{\text{Mass of Sample}} \times 100\%$.

Step2: Identify the values

Here, the mass of the component (tin) is $2.284\ \text{g}$ and the mass of the sample (ore) is $10.00\ \text{g}$.

Step3: Substitute the values into the formula

$\text{Mass Percent of Sn} = \frac{2.284\ \text{g}}{10.00\ \text{g}} \times 100\%$
First, calculate $\frac{2.284}{10.00}= 0.2284$. Then multiply by $100\%$: $0.2284\times 100\% = 22.84\%$.

Answer:

$22.84$