Question

3x + 10y = 31\
2x + 10 = y\
answer attempt 2 out of 5\
(\square, \square) submit answer

Explanation:

Step1: Substitute \( y = 2x + 10 \) into \( 3x + 10y = 31 \)

We know that \( y = 2x + 10 \), so we can replace \( y \) in the first equation with \( 2x + 10 \). This gives us:
\( 3x + 10(2x + 10) = 31 \)

Step2: Simplify and solve for \( x \)

First, distribute the 10 in \( 10(2x + 10) \):
\( 3x + 20x + 100 = 31 \)
Combine like terms:
\( 23x + 100 = 31 \)
Subtract 100 from both sides:
\( 23x = 31 - 100 \)
\( 23x = -69 \)
Divide both sides by 23:
\( x = \frac{-69}{23} = -3 \)

Step3: Find \( y \) using \( y = 2x + 10 \)

Substitute \( x = -3 \) into \( y = 2x + 10 \):
\( y = 2(-3) + 10 \)
\( y = -6 + 10 = 4 \)

Answer:

\((-3, 4)\)