Question

40 n
o→
10 kg
the 10 kg ball experiences an action force of +40 n as it moves to the right. what is the acceleration of the ball?
remember: f = ma
+4 m/s² +0.5 m/s²
-4 m/s² -0.5 m/s²

Explanation:

Step1: Recall the formula \( F = ma \)

We need to find acceleration \( a \), so we can rearrange the formula to \( a=\frac{F}{m} \).

Step2: Substitute the given values

Given \( F = 40 \, \text{N} \) and \( m = 10 \, \text{kg} \), substitute into the formula: \( a=\frac{40}{10} \).

Step3: Calculate the result

\( \frac{40}{10}=4 \, \text{m/s}^2 \). Since the force is \( +40 \, \text{N} \), the acceleration direction is the same as the force, so it's \( +4 \, \text{m/s}^2 \).

Answer:

+4 m/s²