Question

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1. 9 + 50 ÷ 10(3 + 9 - 4) 6) 6 + 28 ÷ 4(4 + 14 - 6)

Explanation:

Problem 5:

Step1: Solve inner parentheses

$3+9-4=8$

Step2: Perform division

$50\div10=5$

Step3: Multiply results

$5\times8=40$

Step4: Add final term

$9+40=49$

Problem 6:

Step1: Solve inner parentheses

$4+14-6=12$

Step2: Perform division

$28\div4=7$

Step3: Multiply results

$7\times12=84$

Step4: Add final term

$6+84=90$

*Correction Note: Rechecking problem 6 arithmetic:

Step1: Solve inner parentheses

$4+14-6=12$

Step2: Perform division

$28\div4=7$

Step3: Multiply results

$7\times12=84$

Step4: Add final term

$6+84=90$

Final corrected answers:
For problem 5: 49
For problem 6: 90*

Final Answer:

For problem 5: 49
For problem 6: 90

Problem 5:

Step1: Calculate inside parentheses

$3+9-4=8$

Step2: Do division first

$50\div10=5$

Step3: Multiply the two values

$5\times8=40$

Step4: Add the remaining number

$9+40=49$

Problem 6:

Step1: Calculate inside parentheses

$4+14-6=12$

Step2: Do division first

$28\div4=7$

Step3: Multiply the two values

$7\times12=84$

Step4: Add the remaining number

$6+84=90$

Answer:

For problem 5: 49
For problem 6: 64