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Question
*86. oxygen and hydrogen react explosively to form water. in one reaction, 6 g of hydrogen combines with oxygen to form 54 g of water. how much oxygen was used?
Step1: Apply the law of conservation of mass
According to the law of conservation of mass, the mass of reactants equals the mass of products. Let the mass of oxygen be $m$. The reactants are hydrogen and oxygen, and the product is water. So, mass of hydrogen+mass of oxygen = mass of water.
Step2: Substitute the known values
We know that the mass of hydrogen is 6 g and the mass of water is 54 g. Substituting into the equation: $6 + m=54$.
Step3: Solve for the mass of oxygen
To find $m$, we subtract 6 from both sides of the equation: $m = 54 - 6$.
$m = 48$ g
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48 g