Question

9x = 45; 32 = 8a; 3x = 36; \frac{x}{5} = 2; 21 = \frac{x}{3}; 8b = 56

Explanation:

Step1: Solve $9x=45$

Divide both sides by 9:
$x=\frac{45}{9}=5$

Step2: Solve $3z=36$

Divide both sides by 3:
$z=\frac{36}{3}=12$

Step3: Solve $21=\frac{x}{3}$

Multiply both sides by 3:
$x=21\times3=63$

Step4: Solve $32=8a$

Divide both sides by 8:
$a=\frac{32}{8}=4$

Step5: Solve $\frac{x}{5}=2$

Multiply both sides by 5:
$x=2\times5=10$

Step6: Solve $8b=56$

Divide both sides by 8:
$b=\frac{56}{8}=7$

Answer:

$x=5$ (from $9x=45$)
$z=12$ (from $3z=36$)
$x=63$ (from $21=\frac{x}{3}$)
$a=4$ (from $32=8a$)
$x=10$ (from $\frac{x}{5}=2$)
$b=7$ (from $8b=56$)