Question

arrange the highlighted bonds in the table below in decreasing order of polarity. that is, pick 1 for the most polar bond, pick 2 for the next most polar bond, and so on. bond polarity h—f: select h—br: select h—i: select

Explanation:

Step1: Recall electronegativity values

Electronegativity of H = 2.2, F = 4.0, Br = 2.96, I = 2.66.

Step2: Calculate electronegativity differences

For H - F: $\Delta\chi=4.0 - 2.2=1.8$.
For H - Br: $\Delta\chi=2.96 - 2.2 = 0.76$.
For H - I: $\Delta\chi=2.66 - 2.2=0.46$.

Step3: Arrange by polarity

Higher $\Delta\chi$ means more polar bond. So H - F is most polar (1), H - Br is next (2), H - I is least polar (3).

Answer:

H—F: 1
H—Br: 2
H—I: 3