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assignment 7.5 1. express in simplest radical form: √36 2. express in s…

Question

assignment 7.5

  1. express in simplest radical form: √36
  2. express in simplest radical form: √28
  3. express in simplest radical form: √24
  4. express in simplest radical form: √75
  5. express in simplest radical form: √48
  6. express in simplest radical form: √18
  7. express in simplest radical form: √32
  8. express in simplest radical form: √72
  9. express in simplest radical form: √160
  10. express in simplest radical form: √12

Explanation:

Step1: Factor out perfect square

$\sqrt{36} = \sqrt{6^2}$

Step2: Simplify the radical

$\sqrt{6^2} = 6$

Step1: Factor out perfect square

$\sqrt{28} = \sqrt{4 \times 7}$

Step2: Split & simplify radical

$\sqrt{4 \times 7} = \sqrt{2^2} \times \sqrt{7} = 2\sqrt{7}$

Step1: Factor out perfect square

$\sqrt{24} = \sqrt{4 \times 6}$

Step2: Split & simplify radical

$\sqrt{4 \times 6} = \sqrt{2^2} \times \sqrt{6} = 2\sqrt{6}$

Step1: Factor out perfect square

$\sqrt{75} = \sqrt{25 \times 3}$

Step2: Split & simplify radical

$\sqrt{25 \times 3} = \sqrt{5^2} \times \sqrt{3} = 5\sqrt{3}$

Step1: Factor out perfect square

$\sqrt{48} = \sqrt{16 \times 3}$

Step2: Split & simplify radical

$\sqrt{16 \times 3} = \sqrt{4^2} \times \sqrt{3} = 4\sqrt{3}$

Step1: Factor out perfect square

$\sqrt{18} = \sqrt{9 \times 2}$

Step2: Split & simplify radical

$\sqrt{9 \times 2} = \sqrt{3^2} \times \sqrt{2} = 3\sqrt{2}$

Step1: Factor out perfect square

$\sqrt{32} = \sqrt{16 \times 2}$

Step2: Split & simplify radical

$\sqrt{16 \times 2} = \sqrt{4^2} \times \sqrt{2} = 4\sqrt{2}$

Step1: Factor out perfect square

$\sqrt{72} = \sqrt{36 \times 2}$

Step2: Split & simplify radical

$\sqrt{36 \times 2} = \sqrt{6^2} \times \sqrt{2} = 6\sqrt{2}$

Step1: Factor out perfect square

$\sqrt{160} = \sqrt{16 \times 10}$

Step2: Split & simplify radical

$\sqrt{16 \times 10} = \sqrt{4^2} \times \sqrt{10} = 4\sqrt{10}$

Step1: Factor out perfect square

$\sqrt{12} = \sqrt{4 \times 3}$

Step2: Split & simplify radical

$\sqrt{4 \times 3} = \sqrt{2^2} \times \sqrt{3} = 2\sqrt{3}$

Answer:

  1. $6$
  2. $2\sqrt{7}$
  3. $2\sqrt{6}$
  4. $5\sqrt{3}$
  5. $4\sqrt{3}$
  6. $3\sqrt{2}$
  7. $4\sqrt{2}$
  8. $6\sqrt{2}$
  9. $4\sqrt{10}$
  10. $2\sqrt{3}$