Question

atoms, elements, compounds & molecules
figure 1.
figure 2.
the particle diagram labeled figure 1 represents a(n) (element or compound). i know this because:
the particle diagram labeled figure 2 represents a(n) (element or compound). i know this because:
each particle in figure 1 is a(n) (atom or molecule).
each particle in figure 2 is a(n) (atom or molecule).
density

1. the density of an unknown metal was found experimentally using water displacement and the data collected is given below.

volume of water in the graduated cylinder
volume of water in the graduated cylinder with metal
30.36 g
61.5 ml
55.0 ml

Explanation:

Step1: Determine particle type in Figure 1

Each particle in Figure 1 consists of two identical atoms, so it is a molecule.

Step2: Determine substance type in Figure 1

Since all particles are identical molecules made of the same - type atoms, it represents an element.

Step3: Determine particle type in Figure 2

Each particle in Figure 2 consists of different atoms bonded together, so it is a molecule.

Step4: Determine substance type in Figure 2

Since the particles are molecules made of different - type atoms, it represents a compound.

Step5: Calculate density

The volume of the metal is \(V = 61.5\ ml-55.0\ ml = 6.5\ ml\). The mass of the metal is \(m = 30.36\ g\). The density formula is \(
ho=\frac{m}{V}\). Substitute \(m = 30.36\ g\) and \(V = 6.5\ ml\) into the formula: \(
ho=\frac{30.36\ g}{6.5\ ml}\approx4.67\ g/ml\).

Answer:

Each particle in Figure 1 is a molecule. Figure 1 represents an element because all particles are identical molecules made of the same - type atoms. Each particle in Figure 2 is a molecule. Figure 2 represents a compound because the particles are molecules made of different - type atoms. The density of the metal is approximately \(4.67\ g/ml\).