Question

balance the following equations: 1. 1 - mg + 2 - o2 → 3 - mgo 2. 3 - cucl2+ -- h2s → -- cus + -- hcl

Explanation:

Step1: Balance the first equation

For the reaction $Mg + O_2
ightarrow MgO$, there are 2 oxygen atoms on the left - hand side and 1 on the right - hand side. Multiply $MgO$ by 2 to get $Mg+O_2
ightarrow 2MgO$. Then, to balance the magnesium atoms, multiply $Mg$ by 2. The balanced equation is $2Mg + O_2=2MgO$.

Step2: Balance the second equation

For the reaction $CuCl_2+H_2S
ightarrow CuS + HCl$, there are 2 chlorine atoms in $CuCl_2$ on the left - hand side. So, multiply $HCl$ by 2 on the right - hand side. The balanced equation is $CuCl_2 + H_2S=CuS+2HCl$.

Answer:

1. $2Mg + O_2 = 2MgO$
2. $CuCl_2 + H_2S=CuS + 2HCl$