Question

1. if a ball with a mass of 0.5 kg is rolling at a velocity of 10m/s, what is the momentum? 3. a cyclist increase their speed from 5 m/s to 15 m/s in 3 second. what is the acceleration?

Explanation:

2.

Step1: Recall momentum formula

The formula for momentum $p$ is $p = mv$, where $m$ is mass and $v$ is velocity.

Step2: Substitute given values

Given $m = 0.5\ kg$ and $v=10\ m/s$. Then $p=(0.5\ kg)\times(10\ m/s)$.

Step3: Calculate momentum

$p = 5\ kg\cdot m/s$.

Step1: Recall acceleration formula

The formula for acceleration $a$ is $a=\frac{v_f - v_i}{t}$, where $v_f$ is final - velocity, $v_i$ is initial - velocity, and $t$ is time.

Step2: Identify given values

$v_i = 5\ m/s$, $v_f=15\ m/s$, and $t = 3\ s$.

Step3: Substitute values into formula

$a=\frac{15\ m/s - 5\ m/s}{3\ s}$.

Step4: Calculate acceleration

$a=\frac{10\ m/s}{3\ s}=\frac{10}{3}\ m/s^2\approx3.33\ m/s^2$.

Answer:

$5\ kg\cdot m/s$

3.