Question

a box is pushed to the right with 6 n while friction pushes to the left with 2 n. what is the net force on the box?
8 n right
4 n right
4 n left
2 n right

Explanation:

Step1: Define positive - direction

Let the right - direction be positive. The pushing force $F_1 = 6N$ (positive) and the frictional force $F_2=- 2N$ (negative as it's in the left - direction).

Step2: Calculate net force

The net force $F_{net}=F_1 + F_2$. Substitute $F_1 = 6N$ and $F_2=-2N$ into the formula: $F_{net}=6+( - 2)=4N$. Since the result is positive, the direction is to the right.

Answer:

B. 4 N right