Question

calculate the average travel time for each distance, and then use the results to calculate. number of washers 1 washer mass = 4.9 g trial time to travel 0.25m ( t_1 )(s) trial #1 2.24 trial #2 2.21 trial #3 2.23 average time to travel 0.50m ( t_2 )(s) trial #1 3.16 trial #2 3.08 trial #3 3.15 average the average time that it takes for the car to travel the first 0.25m is (\boxed{quad}) s. the average time to travel just between 0.25 m and 0.50 m is (\boxed{quad}) s. given the time taken to travel the second 0.25 m section, the velocity would be (\boxed{quad}) m/s.

Explanation:

Step1: Calculate average $t_1$

Add the three trial times for $t_1$, divide by 3.
$\text{Average } t_1 = \frac{2.24 + 2.21 + 2.23}{3} = \frac{6.68}{3} \approx 2.23$ s

Step2: Calculate average $t_2$

Add the three trial times for $t_2$, divide by 3.
$\text{Average } t_2 = \frac{3.16 + 3.08 + 3.15}{3} = \frac{9.39}{3} = 3.13$ s

Step3: Find time for 0.25-0.50 m

Subtract average $t_1$ from average $t_2$.
$\text{Time for second section} = 3.13 - 2.23 = 0.90$ s

Step4: Calculate velocity of second section

Divide distance (0.25 m) by time from Step3.
$\text{Velocity} = \frac{0.25}{0.90} \approx 0.28$ m/s

Answer:

The average time that it takes for the car to travel the first 0.25 m is 2.23 s.
The average time to travel just between 0.25 m and 0.50 m is 0.90 s.
Given the time taken to travel the second 0.25 m section, the velocity would be 0.28 m/s.