Question

calculate the probability of drawing a: blue card, then drawing another blue card, with no replacement. answer as a fraction in lowest terms. enter the numerator.

Explanation:

Step1: Count total and blue cards

There are 10 cards in total and 3 blue cards.

Step2: Calculate first - draw probability

The probability of drawing a blue card on the first draw is $P_1=\frac{3}{10}$.

Step3: Calculate second - draw probability

After drawing one blue card without replacement, there are 9 cards left and 2 blue cards left. So the probability of drawing a blue card on the second draw is $P_2 = \frac{2}{9}$.

Step4: Calculate combined probability

Since these are independent - like (sequential) events, the probability of both events happening is $P = P_1\times P_2=\frac{3}{10}\times\frac{2}{9}=\frac{6}{90}=\frac{1}{15}$.

Answer:

1