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Question
center, spread, and shape of distributions: medium
students at schools in different states calculated the volume of snow that it took to fill one cup of water after the snow had melted. their results, in cups, were: 3.7, 3.0, 3.9, 2.5, 2.5, 2.2
to the nearest tenth of a cup, how much greater was the mean than the median of their calculations?
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Step1: Calculate the mean
The mean $\bar{x}=\frac{3.7 + 3.0+3.9+2.5+2.5+2.2}{6}=\frac{17.8}{6}\approx2.97$.
Step2: Arrange data in ascending - order
$2.2,2.5,2.5,3.0,3.7,3.9$.
Step3: Calculate the median
Since there are 6 data points, the median is the average of the 3rd and 4th ordered values. Median $=\frac{2.5 + 3.0}{2}=2.75$.
Step4: Find the difference
The difference between the mean and the median is $2.97-2.75 = 0.22\approx0.2$.
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$0.2$