Question

check here for instructional material to complete this problem. evaluate the formula n = \frac{z^{2}\cdot p\cdot(1 - p)}{e^{2}} when z = 1.772, p = 0.56, and e = 0.04. n = (round up to the nearest whole number as needed.)

Explanation:

Step1: Calculate $z^{2}$

$z = 1.772$, so $z^{2}=1.772^{2}=3.14$.

Step2: Calculate $1 - p$

$p = 0.56$, so $1 - p=1 - 0.56 = 0.44$.

Step3: Calculate $p\times(1 - p)$

$p\times(1 - p)=0.56\times0.44 = 0.2464$.

Step4: Calculate $z^{2}\times p\times(1 - p)$

$z^{2}\times p\times(1 - p)=3.14\times0.2464 = 0.773696$.

Step5: Calculate $E^{2}$

$E = 0.04$, so $E^{2}=0.04^{2}=0.0016$.

Step6: Calculate $n$

$n=\frac{z^{2}\times p\times(1 - p)}{E^{2}}=\frac{0.773696}{0.0016}=483.56$.

Step7: Round up

Rounding up $483.56$ to the nearest whole - number, we get $n = 484$.

Answer:

$484$