Question

check here for instructional material to complete this problem. let $p(x)=\frac{mu^{x}cdot e^{-mu}}{x!}$ and let $mu = 10$. find $p(4)$. $p(4)=square$ (round to four decimal places as needed.)

Explanation:

Step1: Substitute values

Substitute $\mu = 10$ and $x = 4$ into $P(x)=\frac{\mu^{x}\cdot e^{-\mu}}{x!}$. So we get $P(4)=\frac{10^{4}\cdot e^{- 10}}{4!}$.

Step2: Calculate each part

First, $10^{4}=10000$, $e^{-10}\approx4.539999\times10^{-5}$, and $4!=4\times3\times2\times1 = 24$.

Step3: Compute the result

$P(4)=\frac{10000\times4.539999\times10^{-5}}{24}=\frac{0.4539999}{24}\approx0.0189$.

Answer:

$0.0189$