Question

the chemical formula for sodium bromide is nabr.
a chemist measured the amount of sodium bromide produced during an experiment. she finds that 7.41 g of sodium bromide is produced. calculate the number of moles of sodium bromide produced.
round your answer to 3 significant digits.

Explanation:

Step1: Calculate molar mass of NaBr

Molar mass of Na (sodium) is 22.99 g/mol, molar mass of Br (bromine) is 79.90 g/mol. So molar mass of NaBr is $22.99 + 79.90 = 102.89$ g/mol.

Step2: Use moles formula ($n = \frac{m}{M}$)

Given mass $m = 7.41$ g, molar mass $M = 102.89$ g/mol. So moles $n = \frac{7.41}{102.89}$.
Calculate $\frac{7.41}{102.89} \approx 0.0720$ mol (rounded to 3 significant digits).

Answer:

0.0720 mol