Question

1. choose the the answer.

use charles law to solve for the final volume.
$v_1 = 2.50\\ \text{l}$
$t_1 = 27.0\\ ^\circ\text{c}$
$v_2 = ?$
$t_2 = 337\\ ^\circ\text{c}$
$\bigcirc$ 0.2 l
$\bigcirc$ 1 l
$\bigcirc$ 5 l

Explanation:

Step1: Convert temps to Kelvin

$T_1 = 27.0 + 273.15 = 300.15\ \text{K}$
$T_2 = 337 + 273.15 = 610.15\ \text{K}$

Step2: Apply Charles' Law formula

Charles' Law: $\frac{V_1}{T_1} = \frac{V_2}{T_2}$, rearranged to $V_2 = V_1 \times \frac{T_2}{T_1}$

Step3: Substitute values and calculate

$V_2 = 2.50\ \text{L} \times \frac{610.15\ \text{K}}{300.15\ \text{K}} \approx 5.08\ \text{L}$

Answer:

5L