Question

complete and balance the molecular equation for the reaction of aqueous ammonium bromide, nh₄br, and aqueous lead(ii) acetate, pb(c₂h₃o₂)₂. include physical states. molecular equation: 2nh₄br(aq) + pb(c₂h₃o₂)₂(aq) → pbbr₂(s) + 2nh₄c₂h₃o₂(aq) enter the balanced net ionic equation for this reaction. include physical states. net ionic equation: 2br⁻(aq) + pb²⁺(aq) → pbbr₂(s)

Explanation:

Step1: Identify reactants and products

Reactants are aqueous ammonium bromide ($NH_4Br$) and aqueous lead - (II) acetate ($Pb(C_2H_3O_2)_2$). Products are solid lead - (II) bromide ($PbBr_2$) and aqueous ammonium acetate ($NH_4C_2H_3O_2$).

Step2: Write molecular equation

$2NH_4Br(aq)+Pb(C_2H_3O_2)_2(aq)
ightarrow PbBr_2(s)+2NH_4C_2H_3O_2(aq)$

Step3: Write total ionic equation

$2NH_4^+(aq)+2Br^-(aq)+Pb^{2 + }(aq)+2C_2H_3O_2^-(aq)
ightarrow PbBr_2(s)+2NH_4^+(aq)+2C_2H_3O_2^-(aq)$

Step4: Write net - ionic equation

Cancel out the spectator ions ($NH_4^+$ and $C_2H_3O_2^-$). The net - ionic equation is $2Br^-(aq)+Pb^{2 + }(aq)
ightarrow PbBr_2(s)$

Answer:

Molecular equation: $2NH_4Br(aq)+Pb(C_2H_3O_2)_2(aq)
ightarrow PbBr_2(s)+2NH_4C_2H_3O_2(aq)$
Net - ionic equation: $2Br^-(aq)+Pb^{2 + }(aq)
ightarrow PbBr_2(s)$