Question

complete the following reactions using structural formulas, state the type of reaction, a name of the compound under each organic molecule: 1. type: ______________ ch3-ch2-ch3 + i2 uv light →

Explanation:

Step1: Identify the reaction type

The reaction of propane ($CH_3 - CH_2 - CH_3$) with iodine ($I_2$) under UV - light is a free - radical substitution reaction. In the presence of UV light, iodine radicals are formed which can abstract hydrogen atoms from the propane molecule.

Step2: Write the products

The possible products are 2 - iodopropane ($CH_3 - CHI - CH_3$) and hydrogen iodide (HI). The reaction can be written as $CH_3 - CH_2 - CH_3+I_2\xrightarrow{UV\ light}CH_3 - CHI - CH_3 + HI$. The major product is 2 - iodopropane due to the stability of the secondary radical intermediate.

Step3: Name the compounds

The starting organic molecule $CH_3 - CH_2 - CH_3$ is propane. The product $CH_3 - CHI - CH_3$ is 2 - iodopropane.

Answer:

Type: Free - radical substitution reaction
$CH_3 - CH_2 - CH_3$: Propane
Product $CH_3 - CHI - CH_3$: 2 - iodopropane