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complete the table below, using the diagram of an atom shown at right. …

Question

complete the table below, using the diagram of an atom shown at right.

properties of subatomic particles

namesymbolcharge (in multiples of e)approximate mass (amu)location on diagram
protonsymbol boxcharge boxselect dropdownselect dropdown
name boxsymbol box+11.0 dropdowna dropdown

Explanation:

Step1: Recall electron properties

Electron has charge -1 (in multiples of \( e \)), mass \( \approx 0.0005 \) amu, located in electron cloud (B on diagram). Symbol: \( e^- \) (or as per diagram's symbol, but standard symbol is \( e^- \), charge -1, mass ~0.0005 amu, location B.

Step2: Recall proton properties

Proton has symbol \( p^+ \), charge +1, mass ~1.0 amu, located in nucleus (A on diagram).

Step3: The third row (charge +1, mass 1.0, location A) is neutron? Wait no, neutron has charge 0. Wait, correction: Wait, the third row has charge +1, mass 1.0, location A. Wait, proton has charge +1, mass ~1.0 amu, location nucleus (A). Wait, maybe the third row is proton? Wait no, let's re - check:

Electron:

  • Charge: -1 (since electron is negative, charge in multiples of \( e \) is -1)
  • Mass: ~0.0005 amu (or sometimes approximated as 0 amu for simplicity, but more accurately ~\( 5.486\times10^{-4} \) amu)
  • Location: In the electron cloud (the orbits, labeled B in the diagram)
  • Symbol: \( e^- \) (or the symbol given in the diagram, but standard is \( e^- \))

Proton:

  • Symbol: \( p^+ \)
  • Charge: +1 (in multiples of \( e \))
  • Mass: ~1.0 amu
  • Location: In the nucleus (labeled A in the diagram)

Neutron:

  • Symbol: \( n \)
  • Charge: 0
  • Mass: ~1.0 amu
  • Location: In the nucleus (labeled A in the diagram)

Wait, the third row has charge +1, mass 1.0, location A. So that should be proton? Wait no, if charge is +1, mass 1.0, location A (nucleus), then it's proton. But let's fill the table:

  1. Electron:
  • Charge: -1
  • Mass: ~0.0005 amu (or 0 amu for some tables)
  • Location: B (electron cloud)
  • Symbol: \( e^- \)
  1. Proton:
  • Symbol: \( p^+ \)
  • Charge: +1
  • Mass: 1.0 amu
  • Location: A (nucleus)
  1. The third row: Wait, maybe it's neutron? No, neutron has charge 0. Wait, maybe a typo, but assuming the third row is proton (since charge +1, mass 1.0, location A). Wait, no, neutron has mass ~1.0 amu, charge 0. So maybe the third row is proton, but charge +1, mass 1.0, location A.

Let's fill each row:

  • Electron row:
  • Charge: -1
  • Mass: 0 (or 0.0005, but often 0 in simple tables)
  • Location: B (the outer circles, electron cloud)
  • Symbol: \( e^- \) (or the symbol given, which looks like a small negative symbol)
  • Proton row:
  • Symbol: \( p^+ \) (or the symbol given, which looks like a positive symbol)
  • Charge: +1
  • Mass: 1.0
  • Location: A (the nucleus)
  • Third row: Since charge is +1, mass 1.0, location A, but charge +1 is proton. Wait, maybe the third row is proton, but that would duplicate. Wait, no, maybe the third row is neutron? No, neutron has charge 0. Wait, perhaps the table has a mistake, but following standard subatomic particles:

Electron:

  • Charge: -1
  • Mass: ~0 amu (or \( 5.486\times10^{-4} \) amu)
  • Location: Electron cloud (B)
  • Symbol: \( e^- \)

Proton:

  • Symbol: \( p^+ \)
  • Charge: +1
  • Mass: 1.0 amu
  • Location: Nucleus (A)

Neutron:

  • Symbol: \( n \)
  • Charge: 0
  • Mass: 1.0 amu
  • Location: Nucleus (A)

So if the third row has charge +1, mass 1.0, location A, it's proton. But let's proceed to fill the table as per standard:

Electron:

  • Charge: -1
  • Mass: 0 (or 0.0005)
  • Location: B
  • Symbol: \( e^- \)

Proton:

  • Symbol: \( p^+ \)
  • Charge: +1
  • Mass: 1.0
  • Location: A

Third row (assuming it's proton, but maybe a mix - up, but following the given mass 1.0 and charge +1 and location A, it's proton. But if we consider neutron, charge would be 0. So perhaps the third row is proton.

Answer:

namesymbolcharge (in multiples of \( e \))approximate mass (amu)location on diagram
proton\( p^+ \)+11.0A
proton\( p^+ \)+11.0A(Wait, no, third row should be neutron? But charge is +1. Maybe the table has an error. Alternatively, the third row is proton, and the first two are electron and proton. So correcting:

Electron:

  • Charge: -1
  • Mass: ~0 amu
  • Location: B
  • Symbol: \( e^- \)

Proton:

  • Symbol: \( p^+ \)
  • Charge: +1
  • Mass: 1.0 amu
  • Location: A

Neutron:

  • Symbol: \( n \)
  • Charge: 0
  • Mass: 1.0 amu
  • Location: A

But since the third row has charge +1, it's likely a proton. So the filled table (assuming standard values):

Electron: charge -1, mass ~0, location B, symbol \( e^- \)

Proton: symbol \( p^+ \), charge +1, mass 1.0, location A

Third row (if it's proton, but that's duplicate, so maybe the third row is neutron with charge 0, but the given charge is +1. So perhaps the intended third row is proton, and the first row is electron, second is proton, third is proton (but that's wrong). Alternatively, the diagram has A as nucleus (protons and neutrons) and B as electron cloud (electrons).

So to summarize:

  • Electron: charge -1, mass ~0 amu, location B, symbol \( e^- \)
  • Proton: symbol \( p^+ \), charge +1, mass 1.0 amu, location A
  • The third row (with charge +1, mass 1.0, location A) is proton (but should be neutron? No, neutron has charge 0. So maybe a mistake in the table, but following the given data, it's proton.