Question

complete the tasks to subtract the polynomials vertically.$(1.3t^{3}+0.4t^{2}-24t)-(0.6t^{2}+8-18t)$what is the additive inverse of the polynomial being subtracted?$\bigcirc -0.6t^{2}+(-8)+(-18t)$$\bigcirc -0.6t^{2}+(-8)+18t$$\bigcirc -0.6t^{2}+8-18t$$\bigcirc 0.6t^{2}+(-8)+18t$done

Explanation:

Step1: Identify the subtracted polynomial

The polynomial being subtracted is $0.6t^2 + 8 - 18t$.

Step2: Find its additive inverse

Multiply each term by $-1$:
$-(0.6t^2) + -(8) + -(-18t) = -0.6t^2 + (-8) + 18t$

Answer:

-0.6t² + (-8) + 18t