QUESTION IMAGE
Question
current attempt in progress (a) using the table below, find the average rate of change in the worlds population, p, between 2006 and 2020. give units. world population, in billions of people
| year | 2006 | 2008 | 2010 | 2012 | 2014 | 2016 | 2018 | 2020 |
| population | 6.53 | 6.71 | 6.77 | 7.02 | 7.17 | 7.32 | 7.50 | 7.68 |
round your answer to three decimal places. rate of change of population = (b) if p = f(t) with t in years, estimate f(2012) and give units. use a left - hand interval and round your answer to three decimal places. f(2012) =
Step1: Recall average rate - of - change formula
The average rate of change of a function $y = f(x)$ over the interval $[a,b]$ is $\frac{f(b)-f(a)}{b - a}$. Here, $a = 2006$, $b = 2020$, $f(2006)=6.53$ and $f(2020)=7.68$.
Step2: Calculate average rate of change
$\frac{7.68 - 6.53}{2020 - 2006}=\frac{1.15}{14}\approx0.082$ billion people per year.
Step3: Recall left - hand derivative approximation
The left - hand derivative of $y = f(x)$ at $x = x_0$ is approximated as $\frac{f(x_0)-f(x_0 - h)}{h}$. For $f'(2012)$ with a left - hand interval and $h = 2$ (since the data is given every 2 years), $x_0=2012$, $f(2012) = 7.02$ and $f(2010)=6.77$.
Step4: Calculate $f'(2012)$
$\frac{7.02-6.77}{2}=\frac{0.25}{2}=0.125$ billion people per year.
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(a) The average rate of change is approximately $0.082$ billion people per year.
(b) $f'(2012)=0.125$ billion people per year.