Question

details
no additional details were added for this assignment.
hw5 the limit laws (target l4; §2.3)
score: 5/13 answered: 5/13
question 6
evaluate the limit: $lim_{x \to 3}\frac{x^{2}-8x + 15}{x - 3}$
question help: video message instructor

Explanation:

Step1: Factor the numerator

We factor $x^{2}-8x + 15$ as $(x - 3)(x - 5)$. So the limit becomes $\lim_{x
ightarrow3}\frac{(x - 3)(x - 5)}{x - 3}$.

Step2: Simplify the function

Cancel out the common factor $(x - 3)$ in the numerator and denominator. We get $\lim_{x
ightarrow3}(x - 5)$.

Step3: Evaluate the limit

Substitute $x = 3$ into $x-5$. So $3-5=-2$.

Answer:

$-2$