Question

determine the quantity in moles of rbf that are in 89.6 grams of rbf.

Explanation:

Step1: Find molar mass of RbF

The molar mass of Rb (rubidium) is approximately 85.47 g/mol and F (fluorine) is approximately 19.00 g/mol. So, the molar mass of RbF, $M = 85.47+ 19.00=104.47$ g/mol.

Step2: Calculate moles

Use the formula $n=\frac{m}{M}$, where $m = 89.6$ g and $M = 104.47$ g/mol. So, $n=\frac{89.6}{104.47}\approx0.858$ mol.

Answer:

$0.858$