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differentiate. y = 2x^3 - 8x^2 + 5x + 2 \\frac{dy}{dx}=\\square

Question

differentiate.
y = 2x^3 - 8x^2 + 5x + 2
\frac{dy}{dx}=\square

Explanation:

Step1: Apply power - rule to each term

$\frac{d}{dx}(2x^{3})=2\times3x^{2}$, $\frac{d}{dx}(-8x^{2})=-8\times2x$, $\frac{d}{dx}(5x)=5$, $\frac{d}{dx}(2)=0$

Step2: Combine the results

$6x^{2}-16x + 5$

Answer:

$6x^{2}-16x + 5$