Question

directions:

1. complete the description of the motion of each line segment.

extra practice problem #2
position vs. time

Explanation:

1. For the first segment (0 to 5 seconds): The position increases linearly with time, meaning the object moves away from the starting point at a constant speed. Calculate speed as $\frac{\text{change in position}}{\text{change in time}} = \frac{10-0}{5-0} = 2$ m/s.
2. For the second segment (5 to 10 seconds): The position decreases linearly with time, meaning the object moves back toward the starting point at a constant speed. Calculate speed as $\frac{\text{change in position}}{\text{change in time}} = \frac{0-10}{10-5} = 2$ m/s.

Answer:

1. Line segment 0 to 5 seconds: Moving away from the origin at a constant speed of 2 m/s.
2. Line segment 5 to 10 seconds: Moving toward the origin at a constant speed of 2 m/s.