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directions: evaluate each e 1. $-9^2$ 4. $3^7 \\cdot 3^{-3}$

Question

directions: evaluate each e

  1. $-9^2$
  2. $3^7 \cdot 3^{-3}$

Explanation:

Step1: Evaluate exponent first

$-9^2 = -(9 \times 9) = -81$

Step2: Apply exponent product rule

$3^1 \cdot 3^{-3} = 3^{1 + (-3)} = 3^{-2}$

Step3: Rewrite negative exponent

$3^{-2} = \frac{1}{3^2} = \frac{1}{9}$

Answer:

  1. $-81$
  2. $\frac{1}{9}$