Question

dynamic module practice (ra1fl m05)
reals\。
-7 ≤ p ≤ -1
correct answer:
-7≤p≤-1
progress: 1/2
part 2 of 2
the solution set is graphed as
-11 -10 -9 -8 -7 -6 -5 -4 -3 -2 -1 0 1 2 3 4 5 6 7 8 9 10 11

Explanation:

Step1: Identify the interval endpoints

The inequality is $-7 \leq p \leq -1$, so the endpoints are $-7$ and $-1$.

Step2: Determine the type of points (closed or open)

Since the inequality is "less than or equal to" and "greater than or equal to", we use closed circles (filled circles) at $-7$ and $-1$.

Step3: Draw the line segment

We draw a line segment connecting the closed circle at $-7$ to the closed circle at $-1$ on the number line.

Answer:

To graph $-7 \leq p \leq -1$:

1. Place a closed (filled) circle at $-7$ on the number line (because $p$ can equal $-7$).
2. Place a closed (filled) circle at $-1$ on the number line (because $p$ can equal $-1$).
3. Draw a line segment connecting the two closed circles to represent all the values of $p$ between $-7$ and $-1$ (inclusive).