Question

each atom of an element has the following electron configuration. 1s²2s²2p⁶3s²3p⁶4s²3d¹⁰4p⁶5s²4d¹⁰5p⁵ what is the name of the element? ○ bromine ○ iodine ○ tellurium ○ xenon

Explanation:

Step1: Calculate total electrons

Sum the exponents in the electron configuration:
\(1 + 2 + 2 + 6 + 2 + 6 + 2 + 10 + 6 + 2 + 10 + 5 = 53\).

Step2: Identify element by atomic number

The atomic number (number of electrons in a neutral atom) is 53. The element with atomic number 53 is iodine.

Answer:

B. iodine