Question

for each value of w, determine whether it is a solution to $12 = \frac{w}{4} + 2$.

w	is it a solution?
20	∘ (yes)	∘ (no)
-4	∘ (yes)	∘ (no)
40	∘ (yes)	∘ (no)

Explanation:

Step1: Isolate the variable term

Subtract 2 from both sides:
$$12 - 2 = \frac{w}{4} + 2 - 2$$
$$10 = \frac{w}{4}$$

Step2: Solve for w

Multiply both sides by 4:
$$w = 10 \times 4$$
$$w = 40$$

Step3: Test w=0

Substitute $w=0$ into the equation:
$$12 = \frac{0}{4} + 2$$
$$12 = 0 + 2$$

$$12 eq 2$$

Step4: Test w=20

Substitute $w=20$ into the equation:
$$12 = \frac{20}{4} + 2$$
$$12 = 5 + 2$$

$$12 eq 7$$

Step5: Test w=-4

Substitute $w=-4$ into the equation:
$$12 = \frac{-4}{4} + 2$$
$$12 = -1 + 2$$

$$12 eq 1$$

Step6: Test w=40

Substitute $w=40$ into the equation:
$$12 = \frac{40}{4} + 2$$
$$12 = 10 + 2$$
$$12 = 12$$

Answer:

• For $w=0$: No
• For $w=20$: No
• For $w=-4$: No
• For $w=40$: Yes