Question

electrons and the periodic table
quiz complete
1 2 3 4 5 6 7 8 9 1
which is the electronic configuration for oxygen?
$1s^22s^22p^1$
$1s^22s^22p^3$
$1s^22s^22p^4$
$1s^22s^22p^6$

Explanation:

, 2s holds 2, leaving 4 electrons for the 2p orbital, resulting in the configuration $1s^2 2s^2 2p^4$.

Answer:

, 2s holds 2, leaving 4 electrons for the 2p orbital, resulting in the configuration $1s^2 2s^2 2p^4$.