Question

1. \\((\text{nh}_4)_3\text{po}_4\\)

element	\\(\\#\\) of atoms
total

Explanation:

Step1: Analyze Nitrogen (N)

In \((NH_4)_3PO_4\), the subscript of \(NH_4\) is 3. Each \(NH_4\) has 1 N, so number of N atoms: \(1\times3 = 3\).

Step2: Analyze Hydrogen (H)

Each \(NH_4\) has 4 H, and there are 3 \(NH_4\) groups. So number of H atoms: \(4\times3 = 12\).

Step3: Analyze Phosphorus (P)

In \(PO_4\), there is 1 P atom, so number of P atoms: \(1\).

Step4: Analyze Oxygen (O)

In \(PO_4\), the subscript of O is 4, so number of O atoms: \(4\).

Step5: Calculate Total Atoms

Sum the number of each atom: \(3 + 12 + 1 + 4 = 20\).

Element	# of Atoms
H	12
P	1
O	4
Total	20

Answer:

The number of atoms for N is 3, H is 12, P is 1, O is 4, and total is 20 (as shown in the table above).