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Question
in the equations shown, the variables represent the price of one meal. match the equations to each situation. daniel buys 5 meals. he has a coupon for $3 off the entire order. lucy buys 5 meals. she has a coupon for $3 off each meal. $5(q - 3) = 65$ $5p - 3 = 65$
for Daniel's Situation:
Step1: Analyze Daniel's order
Daniel buys 5 meals, price per meal is \( q \). Total cost before coupon: \( 5q \). Then $3 off entire order, so total cost: LXI2 . This equals 65, so equation: LXI3 ? Wait, no—wait, wait, no: Wait, no, the other equation is \( 5(q - 3) \). Wait, no, let's re - evaluate. Wait, Daniel has $3 off entire order. So total cost is (5 * price per meal) minus 3. So if price per meal is \( p \) (wait, variables: Daniel's variable? Wait, the equations: one is \( 5(q - 3)=65 \), one is \( 5p - 3 = 65 \).
Wait, Lucy has $3 off each meal. So for each meal, price is (price per meal - 3), then 5 meals: \( 5\times(price - 3) \). So Lucy's equation: \( 5(q - 3)=65 \) (if LXI0 is price per meal). Daniel has $3 off entire order: total cost is 5 * price - 3, so \( 5p - 3 = 65 \) (if \( p \) is price per meal).
So:
Daniel: buys 5 meals, $3 off entire order. So total cost = 5 * price - 3. So equation \( 5p - 3 = 65 \).
Lucy: buys 5 meals, $3 off each meal. So each meal is (price - 3), 5 meals: \( 5\times(price - 3) \), so equation \( 5(q - 3)=65 \).
Matching:
- Daniel buys 5 meals. He has a coupon for $3 off the entire order. → \( 5p - 3 = 65 \)
- Lucy buys 5 meals. She has a coupon for $3 off each meal. → \( 5(q - 3)=65 \)
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Daniel buys 5 meals. He has a coupon for $3 off the entire order. → \( 5p - 3 = 65 \)
Lucy buys 5 meals. She has a coupon for $3 off each meal. → \( 5(q - 3)=65 \)