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Question
the exact value of \\(sin \theta\\) in simplest radical form.
(there is a right triangle bcd with right angle at c. the hypotenuse bd is \\(sqrt{96}\\), the side bc is \\(sqrt{24}\\), and the side cd is 8?)
attempt 1 out of 3
answer =
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Step1: Recall sine definition for right triangles
$\sin B = \frac{\text{Opposite to } B}{\text{Hypotenuse}}$
Step2: Identify opposite side to B
Opposite side is $AC=8$, hypotenuse is $AB=\sqrt{75}$
Step3: Substitute values into formula
$\sin B = \frac{8}{\sqrt{75}}$
Step4: Rationalize the denominator
$\sin B = \frac{8\sqrt{75}}{75} = \frac{8 \times 5\sqrt{3}}{75} = \frac{40\sqrt{3}}{75}$
Step5: Simplify the fraction
$\sin B = \frac{8\sqrt{3}}{15}$
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$\frac{8\sqrt{3}}{15}$