Question

for exercise 13, use the graph. 13. the graph of △abc is shown. graph the image of △abc after a translation of 3 units left and 4 units up. (lesson 1)

Explanation:

Step1: Recall translation rule

For a point $(x,y)$ translated $a$ units left and $b$ units up, the new - point is $(x - a,y + b)$. Here $a = 3$ and $b = 4$.

Step2: Translate point A

Suppose the coordinates of point A are $(x_A,y_A)$. The new coordinates of A, $A'=(x_A - 3,y_A + 4)$.

Step3: Translate point B

Suppose the coordinates of point B are $(x_B,y_B)$. The new coordinates of B, $B'=(x_B - 3,y_B + 4)$.

Step4: Translate point C

Suppose the coordinates of point C are $(x_C,y_C)$. The new coordinates of C, $C'=(x_C - 3,y_C + 4)$.

Step5: Plot the new triangle

Plot points $A'$, $B'$, and $C'$ on the same coordinate - plane and connect them to form the image of $\triangle ABC$ after the translation.

Since the original coordinates of the points are not given numerically, we can't give the exact numerical coordinates of the new points. But the general procedure for graphing the translated triangle is as above.

Answer:

Graph the points obtained by translating each vertex of $\triangle ABC$ 3 units left and 4 units up and connect them to form the new triangle.