QUESTION IMAGE
Question
in exercises 1 and 2, copy and complete the table. write your answers in simplest form.
1.
2.
- the side lengths of a triangle are given. determine whether each triangle is
a ( 45^circ\text{-}45^circ\text{-}90^circ ) triangle, a ( 30^circ\text{-}60^circ\text{-}90^circ ) triangle, or neither.
a. ( 5, 10, 5sqrt{3} )
b. ( 7, 7, 7sqrt{3} )
c. ( 6, 6, 6sqrt{2} )
in exercises 4–6, find the values of the variables. write your answers in simplest form.
4.
5.
6.
- you build a two - person tent, as shown. how many square feet of material is
needed to make the tent, assuming the tent has a floor?
Exercise 1 (45°-45°-90° Triangle)
Step1: Recall 45-45-90 side rules
In a 45°-45°-90° triangle, legs are equal ($x_1=x_2=x$), hypotenuse $y = x\sqrt{2}$, so $x=\frac{y}{\sqrt{2}}=\frac{y\sqrt{2}}{2}$.
Step2: Calculate $y$ when $x=5$
$y=5\sqrt{2}$
Step3: Calculate $x$ when $y=4\sqrt{2}$
$x=\frac{4\sqrt{2}\cdot\sqrt{2}}{2}=\frac{4\cdot2}{2}=4$
Step4: Calculate $y$ when $x=\sqrt{2}$
$y=\sqrt{2}\cdot\sqrt{2}=2$
Step5: Calculate $x$ when $y=24$
$x=\frac{24\sqrt{2}}{2}=12\sqrt{2}$
Step1: Recall 30-60-90 side rules
In a 30°-60°-90° triangle: shorter leg $b$, longer leg $a=b\sqrt{3}$, hypotenuse $c=2b$; so $b=\frac{a}{\sqrt{3}}=\frac{a\sqrt{3}}{3}$, $a=\frac{c\sqrt{3}}{2}$, $b=\frac{c}{2}$.
Step2: Calculate $b,c$ when $a=11$
$b=\frac{11\sqrt{3}}{3}$, $c=\frac{22\sqrt{3}}{3}$
Step3: Calculate $a,c$ when $b=9$
$a=9\sqrt{3}$, $c=18$
Step4: Calculate $a,b$ when $c=16$
$b=8$, $a=8\sqrt{3}$
Step5: Calculate $a,c$ when $b=5\sqrt{3}$
$a=5\sqrt{3}\cdot\sqrt{3}=15$, $c=10\sqrt{3}$
Step1: Identify 30-60-90/45-45-90 rules
- 45°-45°-90°: Two equal sides, hypotenuse = side$\cdot\sqrt{2}$
- 30°-60°-90°: Sides in ratio $1:\sqrt{3}:2$
Step2: Analyze part a ($5,10,5\sqrt{3}$)
Ratio: $5:5\sqrt{3}:10 = 1:\sqrt{3}:2$ → 30°-60°-90°
Step3: Analyze part b ($7,7,7\sqrt{3}$)
Does not match either ratio → neither
Step4: Analyze part c ($6,6,6\sqrt{2}$)
Two equal sides, hypotenuse $6\sqrt{2}=6\cdot\sqrt{2}$ → 45°-45°-90°
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| $x$ | 5 | 4 | $\sqrt{2}$ | $12\sqrt{2}$ |
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