QUESTION IMAGE
Question
- $(7h - 1)(-h - 9)$
- $(3v + 2)(-6v^2 + 4v - 2)$
- $(3x - 4)^2$
factor the greatest common factor out of each expression.
- $50k^2 - 60k$
- $7n^3 + 28n^5 - 49n^6$
directions: factor each completely. (4 points each)
- $x^2 + 17x + 70$
- $9n^2 - 11n + 2$
- $9a^2 - 16$
- $2h^2 + 5h + 3$
4) Step1: Apply distributive property (FOIL)
$(7h)(-h) + (7h)(-9) + (-1)(-h) + (-1)(-9)$
4) Step2: Simplify each term
$-7h^2 - 63h + h + 9$
4) Step3: Combine like terms
$-7h^2 - 62h + 9$
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5) Step1: Distribute each term
$3v(-6v^2) + 3v(4v) + 3v(-2) + 2(-6v^2) + 2(4v) + 2(-2)$
5) Step2: Simplify each term
$-18v^3 + 12v^2 - 6v - 12v^2 + 8v - 4$
5) Step3: Combine like terms
$-18v^3 + 2v - 4$
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6) Step1: Expand the squared binomial
$(3x - 4)(3x - 4)$
6) Step2: Apply distributive property
$3x(3x) + 3x(-4) + (-4)(3x) + (-4)(-4)$
6) Step3: Simplify and combine terms
$9x^2 - 12x - 12x + 16 = 9x^2 - 24x + 16$
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7) Step1: Identify greatest common factor (GCF)
GCF of $50k^2$ and $60k$ is $10k$
7) Step2: Factor out the GCF
$10k(5k - 6)$
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8) Step1: Identify greatest common factor (GCF)
GCF of $7n^3$, $28n^5$, $49n^6$ is $7n^3$
8) Step2: Factor out the GCF
$7n^3(1 + 4n^2 - 7n^3)$
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9) Step1: Find pair of factors for 70
Factors of 70 that sum to 17: 7 and 10
9) Step2: Write factored form
$(x + 7)(x + 10)$
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10) Step1: Split middle term
$9n^2 - 9n - 2n + 2$
10) Step2: Factor by grouping
$9n(n - 1) - 2(n - 1)$
10) Step3: Factor out common binomial
$(9n - 2)(n - 1)$
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11) Step1: Recognize difference of squares
$9a^2 - 16 = (3a)^2 - (4)^2$
11) Step2: Apply difference of squares rule
$(3a + 4)(3a - 4)$
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12) Step1: Split middle term
$2h^2 + 2h + 3h + 3$
12) Step2: Factor by grouping
$2h(h + 1) + 3(h + 1)$
12) Step3: Factor out common binomial
$(2h + 3)(h + 1)$
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- $\boldsymbol{-7h^2 - 62h + 9}$
- $\boldsymbol{-18v^3 + 2v - 4}$
- $\boldsymbol{9x^2 - 24x + 16}$
- $\boldsymbol{10k(5k - 6)}$
- $\boldsymbol{7n^3(1 + 4n^2 - 7n^3)}$
- $\boldsymbol{(x + 7)(x + 10)}$
- $\boldsymbol{(9n - 2)(n - 1)}$
- $\boldsymbol{(3a + 4)(3a - 4)}$
- $\boldsymbol{(2h + 3)(h + 1)}$