Question

in favor of the requirements is approximately 61.36 %. if ms. oconnor surveyed 100 parents, approximately 61 of them would be in favor of the new requirement. if there are 1100 parents at the school, how many would ms. oconnor expect to support the requirement? \\(\frac{\square}{\square}=\frac{p}{1100}\\) \\(\square=\square\cdot p\\) \\(\square=p\\) ms. oconnor would expect \\(\square\\) parents to support the requirement.

Explanation:

Step1: Set up the proportion

Let $p$ = number of supporting parents. The proportion uses the approval rate:
$\frac{61}{100} = \frac{p}{1100}$

Step2: Rearrange to solve for $p$

Cross-multiply to isolate $p$:
$p = 1100 \cdot \frac{61}{100}$

Step3: Calculate the value of $p$

Simplify the expression:
$p = 11 \cdot 61 = 671$

Answer:

671