Question

in the figure below, the interior ray bisects the larger angle. what is the value of x?

Explanation:

Step1: Define angle bisector property

Since ray $JG$ bisects $\angle FJH$, $\angle FJG = \angle GJH$.

Step2: Set up equation

$\angle FJG = (x + 69)^\circ$, $\angle GJH = 70^\circ$, so:
$x + 69 = 70$

Step3: Solve for x

Subtract 69 from both sides:
$x = 70 - 69$

Answer:

$1$