Question

in the figure below, the interior ray bisects the larger angle.
what is the value of x?
25
what is the measure of ∠adb?
label optional

Explanation:

Step1: Use angle bisector property

Since ray DB bisects $\angle CDA$, $\angle CDB = \angle ADB$. We know $\angle CDB = 50^\circ$, so $\angle ADB = (2x)^\circ = 50^\circ$.

Step2: Solve for x

Set up the equation: $2x = 50$
$\frac{2x}{2} = \frac{50}{2}$

Step3: Find $\angle ADB$

Substitute $x=25$ into $2x$: $2(25) = 50$

Answer:

The value of $x$ is 25, and the measure of $\angle ADB$ is $50^\circ$